The folder contains 2 XML files:
Code: Select all
SearchBoxRN.xml
ShoppingHomePG.xmlCode: Select all
SearchBoxRN.xml contains this tag:
<customization xmlns="http://xmlns.oracle.com/jrad" version="9.0.6.0.0_45" xml:lang="en-US" customizes="/oracle/apps/icx/icatalog/shopping/webui/SearchBoxRN" xmlns:user="http://xmlns.oracle.com/jrad/user" user:responsibilityKey="east_ppl_ppla_por" user:responsibilityAppShortName="ICX">
ShoppingHomePG.xml contains this tag:
<customization xmlns="http://xmlns.oracle.com/jrad" version="9.0.6.0.0_45" xml:lang="en-US" customizes="/oracle/apps/icx/icatalog/shopping/webui/ShoppingHomePG" xmlns:user="http://xmlns.oracle.com/jrad/user" user:responsibilityKey="east_ppl_ppla_por" user:responsibilityAppShortName="ICX">Code: Select all
user:responsibilityKey="east_ppl_ppla_por"I have a table which contains the new folder ID and responsibility keys - there are 105 in total - for example, for 4 rows of data
Code: Select all
ID responsibilityKey
--------------------------------------------
58571 east_pcy_hd_por
58704 east_pcy_ga_por
58697 east_pcy_pcybs_por
58816 east_pcy_ea_por1. The original folder is copied
2. The new folder is renamed to be the ID of the current row in the table
3. The user:responsibilityKey= section of each xml file is updated to be the responsibilityKey of the current row in the table.
I know this is off topic, but I just wanted to ask the experts here if they had any ideas about how this could be done. I know I could just do it by hand, but the thought of doing that seems like a good way to get RSI, so I wondered if there was a smarter way I could do this.
Any advice much appreciated.
Thanks!