Find and replace

[gajay]

Hello,
I have a text file which has a column containing data like 0.0000, 3.7800, 67.0900, etc. I want to remove the trailing two zeros. How can I do this?

Thanks.

[s_reynisson]

Using POSIX regular expression:
find ([0-9]+.[0-9]{2})[0-9]{2}
replace \1
HTH

edit: it would be safer to limit the search to the right of the decimal
comma, ie. if there is a space (_) there in your file you would use it like:
find ([0-9]+.[0-9]{2})[0-9]{2}_ and replace \1_

[gajay]

Using POSIX regular expression:
find ([0-9]+.[0-9]{2})[0-9]{2}
replace \1
HTH

edit: it would be safer to limit the search to the right of the decimal
comma, ie. if there is a space (_) there in your file you would use it like:
find ([0-9]+.[0-9]{2})[0-9]{2}_ and replace \1_

Thanks for your help but it did not work. I am able to find the text with \.[0-9][0-9]00 but don't know how to remove the last two zeros.

[s_reynisson]

Sorry for not being clear on this, goto Configure->Preferences->Editor
and tick the "Use POSIX regular expression syntax" box.
In the replace dialog tick the "Regular expression" box.

Using POSIX regular expression

[gajay]

Worked like a breeze. Thanks a bunch.