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How to extract LUA error lines using regular syntax?
Posted: Sat Dec 06, 2003 9:57 am
by Stargazer
Hard to understand stuff about regular syntax and traversing messages using it. People, please, help me with this line:
Code: Select all
luac: \\Ilia-comp\_proj\Codes\StargazerCurrent\Scripts\test.lua:16: `=' expected
How it should be look in term of
^\([^(]+\)(\([0-9]+\)) ?
Thanks in advance.
Posted: Sat Dec 06, 2003 5:49 pm
by Bob Hansen
It is not clear to me what you are looking for with your example:
luac: \\Ilia-comp\_proj\Codes\StargazerCurrent\Scripts\test.lua:16: `=' expected
Can you show an example of the results you are looking to find in an example of the source you are looking through?
I don't your RegEx will ever give you a result:
^\([^(]+\)(\([0-9]+\))
Perhaps I am wrong, but this is how I am reading your RegEx, without POSIX format:
Starting from the beginning of the line, excluding one or more "(", select one or more digits within a set of parentheses.
I don't know how this will work because you are excluding all "(", but looking for a string of numbers within parentheses. It seems that this will never find the leading "(" in an expression like (23456) because you have asked to exclude it with
\([^(]+\).