Would like to add 1 digit to a group...
Posted: Tue Jun 05, 2012 10:03 pm
Hello all. I'm not sure if this is possible in textpad but I would like to know if your expertise could assist in the following....
I am trying to replace the third octet in a given IP address to be followed by the next available integer.
For example.
find
10.15.236.3
replace with
10.15.237.3
I have a series of IP addresses in a doc with a lot of other text that needs to stay in place. The IP addresses are unique in the doc so I can search strictly for an IP address and have it replaced with the value I am looking for.
I have tried grouping with textpad but unfortunately I'm not too savvy at regex.
I was thinking along the lines of something like this...
find...
([0-9].*)\.([0-9].*)\.([0-9].*)\.([0-9])
keep...
$1$2$4 but replace $3 with the next subsequent number.
Is there anyway to do this?
I am trying to replace the third octet in a given IP address to be followed by the next available integer.
For example.
find
10.15.236.3
replace with
10.15.237.3
I have a series of IP addresses in a doc with a lot of other text that needs to stay in place. The IP addresses are unique in the doc so I can search strictly for an IP address and have it replaced with the value I am looking for.
I have tried grouping with textpad but unfortunately I'm not too savvy at regex.
I was thinking along the lines of something like this...
find...
([0-9].*)\.([0-9].*)\.([0-9].*)\.([0-9])
keep...
$1$2$4 but replace $3 with the next subsequent number.
Is there anyway to do this?