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Hi

I search the follow string:
ICN-BZ-A-000000-A-S3091-00\d{3}-A-00-2

The \d{3} means 3 numbers.

I want now this sting replace with:
ICN-BZ-A-000000-A-S3091-00\d{3}-A-01-2

(look at the end ..01-2)

After Replace must be like this (example):
ICN-BZ-A-000000-A-S3091-00123-A-01-2

They have any idea?

TextPad's regex engine engine doesn't recognise \d as representing any digit. Use [0-9] instead. For example:

Find what: (ICN-BZ-A-000000-A-S3091-00[0-9]{3}-A-)00(-2)
Replace with: \101\2

[X] Regular expression

The replacement consists of
\1 - what was matched by the first parenthesised subexpression
01 - itself
\2 - what was matched by the second parenthesised subexpression

This assumes you are using Posix regular expression syntax:

Configure | Preferences | Editor

[X] Use POSIX regular expression syntax

Thank you for your advice!

The result looks like this:
A

But i can't find your quote about "use POSIX regular expression syntax".
I have the version 1.1.
In option you have "Use POSIX extended, rather then ECMA Script syntax and rules".

The "Regular expression" and the "Repacement format" is checked.

What can i do to solve the problem?

You are asking about WildEdit in a TextPad forum.

In WildEdit version 2, try

Search for: (ICN-BZ-A-000000-A-S3091-00\d{3}-A-)00(-2)
Replace with: ${1}01${2}

Thank You! Its works done!

ben_josephs wrote:You are asking about WildEdit in a TextPad forum.

The problem is long solved, but I wanted to point out that the OP was asking in the WildEdit forum.

Edward

No. The thread was moved.

Ah, I see, thanks. It's confusing when moving a thread doesn't post and entry with that info.

Edward