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I would like to be able to replace the first 6 characters of a line with sequential line numbers that have leading zeros.
The first six characters in the lines are a combination of Uppercase Alphabetic, Numbers and other characters such as * > ?
I intend to use ^...... (Carat followed by six period characters) to identify the first six characters in the line. What Replace expression do I need to generate line numbers in the form of:
000010
000020
000030
.. etc

I found a solution that worked for me. - Thanks go to Bob Hansen for his reply in another post.

Configure/Word Wrap Off and Block Select Mode
Select the columns you want to fill, replacing the existing numbers.
Choose Edit/ Fill Block/
Select Fill With Numbers vs. characters
Enter number range from 100, increment by 10
Select format for Leading zeros
Choose Fill Mode of Replace,

There is a simpler way:

Search / replace "^......" with "\i(9000010,10)", then
Search / replace "^9" with "".