How to find a specific number of occurrences of a character

jimbo2112 · Post by **jimbo2112** » Tue Jun 16, 2009 3:16 pm

Hi All,

Searched to no avail on this one. As I understand, the reg ex for catching one occurrence of a character you would search with {1}. TextPad does not like this. My aim is to find things like this:

What a BigProblem this is

Using

\([a-z]{1}\)\([A-Z]{1}\)

and replace with

\1 \2

so, the result would be:

What a Big Problem this is

Any suggestions on how to restrict the search length to 1 character?

PS I have switched on case sensitivety!

Many thanks

Jimbo

jimbo2112 · Post by **jimbo2112** » Tue Jun 16, 2009 4:41 pm

Panic over. I had the correct reg-ex in the first place, but for some reason the POSIX option was switched off in preferences. In case anyone was wondering, the actual search string with POSIX in place would not need the `\` before the `(`:

([a-z]{1})([A-Z]{1})

Thanks anyways!

ben_josephs · Post by **ben_josephs** » Tue Jun 16, 2009 4:53 pm

You were mixing Posix and non-Posix syntax.

Anyway, x{1} is equivalent to x , so the braces are unnecessary.

So this is all you need:

Find what: ([a-z])([A-Z])
Replace with: \1 \2

[X] Regular expression

jimbo2112 · Post by **jimbo2112** » Tue Jun 16, 2009 5:11 pm

Indeed I was in the first post.

So in POSIX, the default match value is 1?

ben_josephs · Post by **ben_josephs** » Tue Jun 16, 2009 5:47 pm

In every style of regex (there are many), x matches a single x.

jimbo2112 · Post by **jimbo2112** » Tue Jun 16, 2009 5:48 pm

Cheers Ben, Handy to know.